The fracture strength of tempered glass averages 13.7 (measured in thousands of pounds per square inch) and has standard deviation 2. (a) What is the probability that the average fracture strength of 100 randomly selected pieces of this glass exceeds 13.9

0.15866

Step-by-step explanation:

Given :

μ = 13.7

x = 13.9

Sample size, n = 100

Standard deviation, σ = 2

Recall:

Z = (x - μ) ÷ σ/√n

Z = (13.9 - 13.7) ÷ 2/√100

Z = 0.2 ÷ 0.2

Z = 1

P(x > 13.9) = p(Z > 1) = 0.15866

answer: h

step-by-step explanation:

80 the answer is 80

step-by-step explanation: