Give the trigonometric form of each vector (leave the magnitude as a square root) p= (<2V6, -2V2)

or

Step-by-step explanation:

Find the magnitude of :

Find the direction angle of :

Since is our reference angle, we determine our direction angle by verifying our angle is in Quadrant IV, which is where the vector is located. Therefore,

To represent a vector's magnitude and direction in trigonometric form, we use the form or .

In conclusion, the trigonometric form of the vector is:

or

80° is the measure of gh

step-by-step explanation:

circle f is congruent to circle j

we have two circle with center f and j.

both circles are congruent. the radius of the circle would be equal.

see the attachment for the circle.

we are given ∠efd ≅ ∠gjh

therefore, arc (ed) = arc (gh)     (∴ circle f is congruent to circle j)

but ∠dfe=80°=arc (ed)

therefore, arc (gh) = 80°

thus, 80° is the measure of gh