Solve the quadratic equation by using the quadratic formula. y=-8x^2+6x+3 a) 3±√33/8
b) 3±2√3/8
c) -6±√66/8
d) 3±i√3/4​

A) -3±√33 / 8

Step-by-step explanation:

y = -8x²+6x+3

x = -b±√(b²-4ac) / 2a

x = -(6)±√((6)²-4(-8)(3)) / 2(-8)

x = -6±√(36+96) / -16

x = -6±√(132) / -16

x = -6±2√33 / -16

x = -3±√33 / 8

answer: 7

step-by-step explanation:

5x + 3y = - 4

step-by-step explanation:

the equation of a line in standard form is

ax + by = c ( a is a positive integer and b, c are integers )

express the line first of all in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (7, - 3) and (x₂, y₂ ) = (4, - 8)

m = = -

y = - x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (4, - 8 ), then

- 8 = - + c ⇒ c = -

y = - x - ← in slope-intercept form

multiply all terms by 3 to eliminate the fractions

3y = - 5x - 4 ( add 5x to both sides )

5x + 3y = - 4 ← in standard form