Which associations best describe the scatter plot? (please show a screenshot/picture of it)

Select each correct answer.

Linear association

Nonlinear association

Negative association

Positive association
Scatter plot on a first quadrant coordinate grid. The horizontal axis is labeled Practice time, in hours. The vertical axis is labeled Strikeouts. Points are plotted at (two, thirty), (three, sixty), (five, seventy), (six, one hundred), (six, one hundred ten), (six, one hundred forty), (seven, one hundred thirty), (seven, one hundred fifty), (seven, one hundred seventy), (eight, one hundred twenty), (eight, one hundred forty-five), (eight, one hundred seventy-five), (nine, one hundred fifty), (nine, one hundred seventy-five), (nine, one hundred eighty), (nine, one hundred ninety-five), (ten, one hundred eighty), (ten, two hundred).

hello, sorry being so rude after all that fighting i found it kind of funny, so as me saying sorry here is an answer!

since the table showed her that   2km = 2000m.

to determine, how many km in 2000m, she would divide by 1000.

= 2000 / 1000 = 2 km.

similarly, for 8000m = 8000 / 1000 = 8 km

cheers to savings

~

your pal papaguy

1. when "a" is a root of a polynomial, (x -a) is a factor of it. for the three roots given, the factors of the desired polynomial are (x +2)(x -1/2)(x -3).

in order to make the leading coefficient be negative, we need to multiply this product by a negative number. any negative number will do, but we choose a small (magnitude) value that will eliminate the fraction: -2.

then

f(x) = -2(x +2)(x -1/2)(x -3) = -(x +2)(2x -1)(x -3)

= -(2x² +3x -2)(x -3)

= -(2x³ -3x² -11x +6)

f(x) = -2x³ +3x² +11x -6

2. a graph created by the desmos on-line graphing calculator is shown, and the zeros are highlighted.

3. as indicated in part 1, the multiplier of this equation can be anything and the zeros will remain the same. you want a negative leading coefficient, so the "anything" is restricted to any of the infinite number of numbers that will make that be the case.