What would be the shape of the graph r = 2 cos 6, given that 0 = 0, 3.14/6,3.14/3,3.14/2 -semi circle in 1 quad
-straight line in 1 quad
-straight line in 3 quad
-semi circle in 3 quad

the answer is c

step-by-step explanation:

step-by-step explanation:

the first 5 right here the next 5 i will upload as separate question

false

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18

step-by-step explanation:

draw the shape and you will see that f and k are actually at adjacent vertices (points of the hexagon that are neighboring).   so find the distance between (1,2) and (4,2).   that is easy since (1,2) and (4,2) is just a vertical distance to count, which is 3.   it is a regular polygon which means all sides are congruent.   you have 6 sides (hexa) so multiply 6 by 3 to receive 18.