Solve 252x−1=400 for x. Which answer shows the correct steps?

A) 252x−12x−12x−12x2xx=400=log25400=lo g400log25=log400log25+1=2.8613…≈1.4 31

B) 252x−12x−1ln252x−1x⋅ln25xx=400=log4 00log25=ln400=ln400=ln400ln25≈1.861

C) 252x−1ln252x−1(2x−1)⋅ln252x−ln252x2 xx=400=ln400=ln400=ln400=ln400+ln25 =9.2103…≈4.605

D) 252x−1log252x−1(2x−1)⋅log252x−12x2x x=400=log400=log400=log(40025)=log( 16)+1=2.2041…≈1.102