PLEASE HELP solve for x​

/2=1.41

/5=2.24

(a)^2+(b)^2=(c)^2

(1.41)^2+(b)^2=(2.24)^2

2+(b)^2=5

(b)^2=5-2

(b)^2=3

b=/3 or 1.73

Step-by-step explanation:

for a triangle, a missing value of the side can be found using pythagorean theorem which is (a)^2+(b)^2=(c)^2

replace it with the given value.

*note:(c)^2 should be the hypotenuse

inverse of +ve is -ve

inverse of square is square root