Select the correct answer from each drop-down menu. Solve this system of equations using a matrix inverse.
The elements of R1 are A. 1,-3,1 B. 1,2,-2 C. 1,3,-1 D. 2,3,-1
The elements of R2 are A. 4,-3,2 B. 4,-1,2 C. 6,-2,1 D. 6,-3,1
The elements if R3 are A. 2,-1,-2 B. 2,-1,-3 C. 1,-2,-2 D. 3,-2,-3
The solution of this system is (x, y,z)= A. (3,7,4) B. (4,6,3) C. (6,4,3) D. (7,3,4)

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length

i dont know men

step-by-step explanation:

answer:   2 multiplied by x =24

step-by-step explanation: