At a local seaside, a vendor sells single-cone ice-creams for $3 and double-cone ice-creams for $4.50. The vendor stocks a maximum of 70 single cones and a maximum of 45 double cones. For the afternoon he expects to sell no more than 50 ice-creams.

The answer is below

Step-by-step explanation:

Let x represent the number of single cone ice cream and let y represent the number of double cone ice cream.

Since the vendor stocks a maximum of 70 single cones and a maximum of 45 double cones. hence:

0 < x ≤ 70, 0 < y ≤ 45      (1)

The vendor expects to sell no more than 50 ice creams, hence:

x + y ≤ 50

Plotting the constraint using geogebra online graphing tool, we can see that the solution to the problem is at (5, 45)

Since the vendor sells single-cone ice-creams for $3 and double-cone ice-creams for $4.50, hence:

Revenue = 3x + 4.5y

At the point (5, 45), the revenue is:

Revenue = 3(5) + 4.5(45) = $217.5

srry idk

step-by-step explanation: