500 gallons of water is being drained at a rate of 4 gallons per hour, If y is the number os gallons of water in the tank after being drained for x hours, which equation represents the situation?

4x + y = 500

Step-by-step explanation:

Given:

Volume of water = 500 gallons

Water drained rate = 4 gallon per hour

Find:

Equation

Computation:

Total volume of water left in tank = y

Number of hour water drained = x

So,

Volume of water - Total volume of water left in tank = Water drained rate[Number of hour water drained]

500 - y = 4x

So,

Water drained;

4x + y = 500

answer: it is d

step-by-step explanation:

a. 12.5 kg

step-by-step explanation:

f = ma

so

m = f/a = (2500 n)/(200 m/s²) = 12.5 kg

1 n = 1 kg·m/s²