Does anyone know a edulastic hack?

The Pacing Method:

Use Edulastic to help convey weekly expectations and track student progress along the way

You can set up Edulastic to function as your check-in-tool with students, and Edulastic will help you in gathering student data during this process (#Edulasticforthewin!). This can help in estimating student participation grades and preparing reports to supervisors. It can also help with pacing and students staying on task.

When I was a high school science teacher I would structure “Check ins” with my students on written handouts that students had to present to me for my signature (upon meeting and discussing project updates, hearing feedback from me etc.). If I had access to Edulastic tools then, I could have instead coordinated these check ins digitally and privately using Edulastic. They could check-in on their own time, at home or at school. That makes things a heck of a lot more efficient than having students form a line waiting to talk to me at my desk! You can set this up to occur at the every other day mark, weekly mark, biweekly, or even monthly mark depending upon length and scope of a project in place.

Check out how this might look in Edulastic:

Step-by-step explanation:

x is variable or an unknown value to find

example:

2x = 5 which means x = 3

starting with:    

5 + x - 12 = 2x - 7   

5 + x - 12 - x = 2x - 7 - x (subtract x from both sides)   

5 - 12 = x - 7 (combine and cancel x's from both sides)   

5 - 12 + 7 = x - 7 + 7 (add 7 to both sides)   

0 = x (add numbers together on both sides)       

so in order for the equation to be true, x must be 0.   

trying x = -0.5   

5 + x - 12 = 2x - 7 (original equation)   

5 + -0.5 - 12 = 2(-0.5) - 7 (plug in value of x)   

5 + -0.5 - 12 = -1 - 7 (did multiplication)   

-7.5 = -8 (did addition on both sides)       

since -7.5 is obviously not equal to -8, the value of -0.5 for x is wrong.   

trying x = 0   

5 + x - 12 = 2x - 7 (original equation)   

5 + 0 - 12 = 2(0) - 7 (plug in value of x)   

5 + 0 - 12 = 0 - 7 (did multiplication)   

-7 = -7 (did addition on both sides)       

since -7 equals -7, that demonstrates that the value of 0 for x is correct.   

trying x = 1   

5 + x - 12 = 2x - 7 (original equation)   

5 + 1 - 12 = 2(1) - 7 (plug in value of x)   

5 + 1 - 12 = 2 - 7 (did multiplication)   

-6 = -5 (did addition on both sides)       

since -6 is obviously not equal to -5, the value of 1 for x is wrong.