Solve the following quadratic.

`x^{2}\ +\ 4x\ +\ 1\ =\ 6`

x = -5 and 1

Step-by-step explanation:

1. Subtract 6 from both sides to get x²+4x-5=0

2. Factor the quadratic equation. Find two numbers that have a sum of 4 and a product of (-5). The numbers 5 and (-1) add to 4 and multiply to get -5

3. The factored equation is (x+5)(x-1)=0

4. Set each factor to equal zero and solve for x.

x+5=0 ... x=-5

x-1=0 ... x=1

i = 2 / - 5

step-by-step explanation:

evaluation of ( 2 - 4 ) ( p + q ) when p = 2 and q = 5 i, by putting values of p and q,                                                                    

i got 86 for this

hope this !

if you need an explanation just ask