A person invests 1000 dollars in a bank. The bank pays 4% interest compounded quarterly. To the nearest tenth of a year, how long must the person leave the money
in the bank until it reaches 1600 dollars
A=P(1+)
"
Sant Pere

The person must leave the money for 11.8 years until the investment reaches 1600 dollars.

Step-by-step explanation:

Given that a person invests 1000 dollars in a bank, and the bank pays 4% interest compounded quarterly, to determine to the nearest tenth of a year, how long must the person leave the money in the bank until it reaches 1600 dollars the following calculation must be done:

1000 x (1 + 0.04 / 4) ^ Xx4 = 1600

1000 x 1.01 ^ 4X = 1600

1010 ^ 4X = 1600

X = 11.8

Therefore, the person must leave the money for 11.8 years until the investment reaches 1600 dollars.

56.6

step-by-step explanation:

the ratio of the perimeters is equal to the scale.

the ratio of the areas is equal to the square of the scale.

34 / 20 = k

a / 19.6 = k²

substituting:

a / 19.6 = (34 / 20)²

a = 19.6 (34 / 20)²

a ≈ 56.6

cosine

step-by-step explanation: