Given:BK=CH Which additional congruence statement could you use to prove that ∆BJK ≅ ∆CFH by the HL Theorem?

B

Step-by-step explanation:

The hl theorem says that if we have two right triangles that have a congruent hypotenuse and a congruent leg, the two triangles are congruent

in this case the exercise says the two leg are congruent, so we have to say that the two hypotenuse are congruent

So

JB congruent to FC

point a is the center of the circle that passes through points e, f, and g and the center of the circle that passes through points x, y, and z.