Find the probability of each event. A politician is about to give a campaign speech and is holding a stack of thirteen cue cards, of which the first 3 are the most important. Just before the speech, she drops all of the cards and picks them up in a random order. What is the probability that cards #1, #2, and #3 are still in order on the top of the stack?

The probability that cards # 1, # 2, and # 3 are still in order on the top of the stack is 0.045%.

Step-by-step explanation:

Since a politician is about to give a campaign speech and is holding a stack of thirteen cue cards, of which the first 3 are the most important, and just before the speech, she drops all of the cards and picks them up in a random order, to determine what is the probability that cards # 1, # 2, and # 3 are still in order on the top of the stack, the following calculation must be performed:

1/13 x 1/13 x 1/13 = X

0.076 x 0.076 x 0.076 = X

0.00045 = X

0.00045 x 100 = 0.045

Therefore, the probability that cards # 1, # 2, and # 3 are still in order on the top of the stack is 0.045%.

(c, 0) i might be wrong so don't put full faith on my answer

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions