Suppose you are choosing a 6 digit personal access code. This code is made up of 4 digits chosen from 1 to 9, followed by 2 letters chosen from A to Z. Any of these digits or letters can be repeated. Use the counting principle to find the total number of personal access codes that can be formed

4435236

Step-by-step explanation:

Total digits of code = 6

Code options for first 4 digits = any of 1 - 9 = 9 options

Code option for last 2 digits = A - Z = 26 options

Code number 1 = 9 possible values

Code number 2 = 9 possible values

Code number 3 = 9 possible values

Code number 4 = 9 possible values

Code number 5 = 26 possible values

Code number 6 = 26 possible values

Hence, total number of possible access codes :

9 * 9 * 9 * 9 * 26 * 26

9^4 * 26^2

= 4435236 possible ways

x² + 3x + 7 = 0       [ax² + bx + c]

a = 1

b = 3

c = 7

quadratic formula:

    (+/- is this ±)

plug in the numbers into the variables

your answer is a

52 \43 i don't know this i tried