In circle Q with m ∠ P Q R = 60 m∠PQR=60 and P Q = 16 PQ=16 units find area of sector PQR. Round to the nearest hundredth.

i dont no

Step-by-step explanation:

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56.6

step-by-step explanation:

the ratio of the perimeters is equal to the scale.

the ratio of the areas is equal to the square of the scale.

34 / 20 = k

a / 19.6 = k²

substituting:

a / 19.6 = (34 / 20)²

a = 19.6 (34 / 20)²

a ≈ 56.6

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