(I’ll give brainliset) Your friend makes a two dimensional model of a dividing cell as shown. The total area of the dividing cell is 350 square inches. What is the area of the shaded region to the nearest whole inch? nearest whole inch?

149.04 in^2

Step-by-step explanation:

The image of the question can be seen below.

In the image, we can see two circles that intersect at a given point.

We know that the total area of the image is 350 in^2

We want to find the area of the shaded part.

Ok, this seems to be hard, so instead, let's find the area of the two non-shaded parts (two semicircles) and just subtract that area from the total area of 350in^2

The two non-shaded parts are half a circle of diameter 16 inches.

We know that for a circle of diameter D, the area is:

A = pi*(D/2)^2

Where pi = 3.14

And because we want to find the area of two semicircles of diameter 16 inches, is exactly the same as finding the area for a single circle of diameter 16 inches.

This is:

A = 3.14*(16in/2)^2 = 3.14*(8in)^2 = 200.96 in^2

Now we can just subtract this from the total area:

shaded area = total area - A

shaded area = 350 in^2 - 200.96 in^2

shaded area = 149.04 in^2

f is the midpoint of

y = 2x

step-by-step explanation:

if you divide each number in the sequence, you'll see that they all have a multiple factor of 2. each number in the series, and any other numbers which may continue, will be multiplied by 2. therefore, y is the next number in the sequence, and x is the current one, so, our formula will be y = 2x.