Exercise. 1. Find an equation of the plane passing through the point (-2, 8, 10) and perpendicular to the
line
I = 1+t, y = 2t and =4 - 3t.
State both the scalar equation and the linear equation of the plane.​

answer:   x = 3 + √11     and     x = 3 - √11

step-by-step explanation:

x² - 6x + 9 = 11

(x - 3)² = 11

x - 3 = ±√11

    x = 3 ± √11

x = 3 + √11     and     x = 3 - √11

d 600 because 15*10*2=300

300+300=600

step-by-step explanation:

step-by-step explanation:

the triangles are similar. therefore the corresponding sides are in proportion:

              cross multiply

            divide both sides by 32