Two groups went bowling. Here are the scores from each group. Group A: 80, 100, 190, 110, 70, 90, 130

Group B: 50, 110, 100, 120, 107, 140, 150

70

80

190

50 60

90 100 110 120 130 140 150 160 170 180

score in points

1. Construct two box plots, one for the data in each group.

2. Which group shows greater variability? Explain how you know.

Group A has greater variability

Step-by-step explanation:

Group A: 80, 100, 190, 110, 70, 90, 130

The variability of group A data :

Taking the range :

Maximum  = 190 ; Minimum = 70

Range = Maximum - Minimum ; 190 - 70 = 120

Group B : 50, 110, 100, 120, 107, 140, 150

The variability of group B data :

Taking the range :

Maximum  = 150 ; Minimum = 50

Range = Maximum - Minimum ; 150 - 50 = 100

Hence, Group A has greater variability

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

b. would be the answer : )

step-by-step explanation:

step 1: add -16x to both sides.

16x−4y+−16x=64+−16x  

−4y=−16x+64

step 2: divide both sides by -4.

−4y /-4 = -16x + 64/-4

answer:   y=4x−16

hope i'm right