Exhibit 11-1 Last year, the standard deviation of the ages of the students at UA was 1.81 years. Recently, a sample of 10 students had a standard deviation of 2.1 years. We are interested in testing to see if there has been a significant change in the standard deviation of the ages of the students at UA. Refer to Exhibit 11-1. The test statistic is

test statistic = 12.115

Step-by-step explanation:

Given data :

std = 2.1 years

n = 10

( std )^2 = 4.41

determine the test statistic

apply a two-tailed test ( chi squared test for one population variance )

test statistic

λ^2 =   ( Referring to Exhibit 11-1 )

      = ( 10 - 1 )*(2.1)^2 / 3.2761

      = 12.115

9.55 degrees.

step-by-step explanation:

the given angle is

1 cycle is equal to 2π radians. so 4π will be equal to two cycles.

5.166667π-4π = 1.166667π

hence, this angle goes a little more than negative x axis.

1.166667π-π= 0.166667π

hence, the reference angle is 0.166667π radians.

1 radian = 57.2958 degrees

now, in degrees, this should be equals to 9.55 degrees.

50*10 is greater

step-by-step explanation:

if you add the zero from 10 to 50, it will give you a bigger number.