A rectangle has vertices (–1, 1), (–4, 1), (–1, 3), and (–4, 3). If the rectangle is rotated 90° clockwise, what algebraic rule can be used to find each of the new vertices? (x, y) → (–y, x)

(x, y) → (–y, –x)

(x, y) → (x, –y)

(x, y) → (y, –x)

y/x=18

step-by-step explanation:

it is not that hard all u have to do is plot the graph

step-by-step explanation:

m∠5 + m∠3 = m∠1   is true.

m∠5 + m∠6 = 180 is true

m∠2 +m∠3 = m∠6   is true

m∠2 +m∠3 +m∠5 = 180   is true

the polynomial is a perfect square trinomial of the form a^2-2ab+b^2:

option a. true

step-by-step explanation:

9x^2-12x+4

comparing with the form a^2-2ab+b^2

1.) a^2=9x^2

solving for a: square root both sides of the equation:

sqrt(a^2)=sqrt(9x^2)

a=sqrt(9) sqrt(x^2)

a=3x

2.) b^2=4

solving for b: square root both sides of the equation:

sqrt(b^2)=sqrt(4)

b=2

to be a perfet square trinomial 2ab must be equal to 12x. let's check:

2ab = 2 (3x) (2)

2ab = 12x

correct