On the same exam, Alyssa's friend Jessie answered three times more questions correct than incorrect. Who got a higher percentage of the test questions correct, Alyssa or Jessie?

Complete question is;

Alyssa took a math test with 20 questions and she answered 16 questions correctly. In order get an A, she needs to answer at least 90 percent of the questions correctly.

A) Did Alyssa get an A on this math test? Explain.

B) How many questions would Alyssa need to answer correctly in order to get an A?

C) On the same exam, Alyssa's friend Jessie answered three times more questions correct than incorrect. Who got a higher percentage of the test questions correct, Alyssa or Jessie

A) she didn't get an A because she scored less than 90%.

B) She will need to answer 18 correctly to get an A.

C) Alyssa had a higher percentage.

Step-by-step explanation:

A) Alyssa answered 16 out of 20 questions correctly.

Converting this to percentage gives;

16/20 × 100% = 80%

Now,we are told she needs at least 90% correct answers to get an A.

She scored 80% which is less than 90% mark of A, therefore she didn't get an A.

B) Let the number of minimum questions to answer correctly out of 20 be x.

Thus, since it is 90%.

Then;

x/20 × 100% = 90%

making x the subject;

x = 90 × 20/100

x = 18

She will need to answer 18 correctly to get an A.

C) her friend Jessie answered three times more questions correct than incorrect.

This means for every 4 questions answered, she had 3 correct and 1 incorrect.

Thus,

For 4 questions she had 3 correct answers, then for 20 questions, she will have: 20 × 3/4 = 15 correct questions

Which corresponds to;

15/20 × 100% = 75%

Thus, Alyssa had a higher percentage.

you didn't post any answer choices, so its not 100% clear what your teacher is looking for

however, log(15/7) is equivalent to log(15) - log(7)

i'm using the rule log(x/y) = log(x) - log(y)