Which relationship is true for the triangle based on the Law of Sines? $\frac{\sin100\degree}{10}=\frac{\s in B}{100}$ $\frac{\sin100\degree}{6}=\frac{\si n C}{7}$ $\frac{\sin100\degree}{6}=\frac{\si n B}{10}$ $\frac{\sin100\degree}{10}=\frac{\s in C}{6}$

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x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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