Two geometry questions in the attached photos - If I have a line, do I have a plane? & If I have three points, do I always have a plane?

18) A: only if you have an additional point not on the line.

19) D: No, because all the points may be on the same line.

Step-by-step explanation:

There are basically 4 ways we can determine a plane and they are;

- When we have three non - collinear points: What this means is that if we have three points that are not on one line, then it means that only one particular plane can pass through those points.

- When we have a line and a point that's not on the line

- When we have two lines that intersect each other.

- When we have two lines that are parallel to each other.

From the four conditions above, we can now answer the question;

18) You can only have a plane if there is an additional point not on the line.

Option A

19) Having just three points may not always be sufficient to have a plane because it's possible that the three points may be on the same line which is not a condition for a plane. Thus, option D is correct.

x = 17

step-by-step explanation:

in the given figure, two triangles are inscribed in a circle where ∠bae ≅ ∠dae which makes the side be and de equal so we can write it as:

3x - 24 = x + 10

solving this equation for x to get:

3x - x = 10 + 24

2x = 34

x = 34/2

x = 17

therefore, the value of x = 17.

the rocket cannot penetrate the ground, in a contextual sense, therefore the roots of this equation should be the domain of this function. i'll let you find the roots of this quadratic equation (hint: use the quadratic formula:  

1- c

2-a

step-by-step explanation:

mark brainliest!