PLEASE HELP, WILL MARK BRAINLIEST! A circular pool has a footpath around the circumference. The equation x2 + y2 = 2,500, with units in feet, models the outside edge of the pool. The equation x2 + y2 = 3,422.25, with units in feet, models the outside edge of the footpath. What is the width of the footpath?

8,5 feet

Step-by-step explanation:

The equation of the form

x² + y² = (r)²

Is the equation of the circumference

We have for the pool:

x²  +  y²  = 2500      ⇒  x²  +  y²  = (50)²

And for the outside edge of the footpath

x²  +  y²  = 3422,25  ⇒  x² + y²  = (58,5)²

So we obtain the radius of each circumference

For the outside edge of the pool  r₁  = 50 feet

For the outside edge of the footpath r₂ = 58,5  feet

Then the width of the footpath is  58,5  - 50  =  8,5 feet

step-by-step explanation:

through just a quick inspection, one can see that the graph of this cubing function starts in quadrant iii and ends in quadrant i.   when x = 0, y = 3, so the y-intercept is (0, 3).

if graphs are part of the problem statement, share them.   .