Classify the function as linear or quadratic and identify the quadratic, linear, and constant terms. f(x) = 6x^2 + x − 12

A. quadratic function; quadratic term: −12x^2; linear term: −6x; constant term: −12

B. linear function; linear term: x; constant term: −12

C. linear function; linear term: 6x^2; constant term: −12

D. quadratic function; quadratic term: 6x^2; linear term: x; constant term: −12

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x

option 3 . (5x + 1) - (-10x + 6)

step-by-step explanation:

option 1 :

(4x + 3) + (-9x + 4)

or 4x+3 -9x + 4

or -5x + 7

option 2

(x - 2) - (6x - 9)

or x-2-6x + 9

or -5x + 7

option 3

(5x+ + 6)

or 5x + 1 + 10x -6

or 15x -5

option 4

-4x+2x+7-3x

-7x + 2x + 7

-5x + 7

hence only option 3 did   not satisfy the given simplify expression.

jfkc

step-by-step explanation:

jhcxzbfzc