A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using this equation, find the
time that the rocket will hit the ground, to the nearest 100th of second.
y = -16x^2+ 181x + 59

answer: the answer is (b) amie should have multiplied

step-by-step explanation: given a sphere and a cylinder with same radius and height.

let, 'r' be the radius of the cylinder and sphere and 'h' be the height of the cylinder. according to the question,

r = h.

now, the volume of the sphere will be

and the volume of the cylinder will be

therefore, we have

thus, ammie should have multiplied the volume of the sphere

i did it myself and i got 4.2 (b) hope its right

step-by-step explanation:

just go here

its what i use

step-by-step explanation:

ιт 45,000 мєтєяѕ тσ ℓαѕ νєgαѕ

нσρє ι ¢συℓ∂ нєℓρ