Write the equation of a parabola that has a vertex of (-1, 4) and that is 2 times narrower than f(x) = x^2, where the vertex is a minimum.

x = 3 ± √(5+y)

answer: cos [   arcsin (3/5) - arccos (1/2) ] =

step-by-step explanation: × = 3/5 = 0.6--> x = 36.87 and x = 180 - 36.87 = 143.13 deg

cos y = 1/2 --> y = +- 60 deg a. cos (x - y) = cos (143.13 - 60) = cos 83,13  

=

0.12

b. cos (36.87 - 60) = cos (-23.23) = 0.92

the height of the surface increases from the center out to the sides of the road

it is c!

then