Applied Statistics and Probability for Engineers 9-75. Human oral normal body temperature is believed to be
98.6° F, but there is evidence that it actually should be 98.2° F
[Mackowiak, Wasserman, Steven and Levine, JAMA (1992, Vol.
268(12), pp. 1578–1580)]. From a sample of 52 healthy adults,
the mean oral temperature was 98.285 with a standard deviation
of 0.625 degrees.
(a) What are the null and alternative hypotheses?
(b) Test the null hypothesis at α = 0.05.
(c) How does a 95% confidence interval answer the same
question?

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)

134.6 us dollars

step-by-step explanation:

1 us dollar = 1.33 canadian dollars

so, 150 us dollars = 150 × 1.33 = $199.5.

in canada, the money mitchell spent = 20 canadian dollars.

remaining canadian dollars with him = 199.5 - 20 = 179.5.

after mitchell returned to us, he exchanged the remaining canadian dollars to us dollars.

179.5 canadian dollars = 179.5 × 0.75 = 134.6 us dollars.

her total is 2

  -3+5=2