Expand and simplify

(x-2)(2x+3)(x+1)

2x³ + x² - 7x - 6

Step-by-step explanation:

(x-2)(2x+3)(x+1)

first: (x-2)(2x+3) = 2x² + 3x - 4x -6 = 2x² - x - 6

second: (2x² - x - 6)(x+1) = 2x³ + 2x² - x² - x - 6x - 6 = 2x³ + x² - 7x - 6

(x-2) [(2x+3)(x+1)]

(x-2)[(2x²+2x+3x+3)]

(x-2)[(2x²+5x+3)]

(x-2) (2x²+5x+3)

2x³+5x²+3x-4x²-10x-6

Answer = 2x³+x²-7x-6

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

step-by-step explanation:

6.48/4 4 goes into 6.48 1.62 times