A hexagon forms a semi-regular tessellation with which of the following regular polygons?
A. Square and equilateral triangle
B. Dodecagon and equilateral triangle
C. Trapezoid and pentagon
D. Trapezoid and octagon

x=6 and x=3

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v = 1/3 a^2h

step-by-step explanation:

the volume is 1/3 a^2h.

answer: 12,000

step-by-step explanation: first you ar e supposed to add. then multiply then subtract

unless you made a typo, the answers are both a and c.

step-by-step explanation:

1.5/3 is .5 whereas 3/9 is .3333333 not proportional

22/33 is .66666 and 4/6 is also .66666 proportional

2/4 is .5 whereas 142/213 is .66666 not proportional

14/7 is 2 and 7/3.5 is also 2 proportional

you could've also checked it by doing this simple division:

if the larger fraction divides with the smaller fraction to equal 1, it is proportional. so let me show you what i mean:

when i divide 22/33 by 4/6 i get 1, so we know it is proportional, and it is the same with 14/7 and 7/3.5. now if i divide 3/9 by 1.5/3 i get .66666 so therefore we know it is not proportional.

there are many ways to do this so i wanted to show you some possible ways.