subject
Mathematics, 06.05.2021 17:30 bae2080

βˆ’7x+8βˆ’10x 2
=7minus, 7, x, plus, 8, minus, 10, x, squared, equals, 7
Choose 1
Choose 1

(Choice A)
A
x =\dfrac{7 \pm \sqrt{89}}{-20}x=
βˆ’20
7Β±
89
​

​
x, equals, start fraction, 7, plus minus, square root of, 89, end square root, divided by, minus, 20, end fraction

(Choice B)
B
x =\dfrac{-9 \pm \sqrt{249}}{-12}x=
βˆ’12
βˆ’9Β±
249
​

​
x, equals, start fraction, minus, 9, plus minus, square root of, 249, end square root, divided by, minus, 12, end fraction

(Choice C)
C
x =\dfrac{2 \pm \sqrt{29}}{5}x=
5
2Β±
29
​

​
x, equals, start fraction, 2, plus minus, square root of, 29, end square root, divided by, 5, end fraction

(Choice D, Checked)
D
x =-1,\frac{7}{10}x=βˆ’1,
10
7
​

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Answers: 1

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βˆ’7x+8βˆ’10x 2
=7minus, 7, x, plus, 8, minus, 10, x, squared, equals, 7
Choose 1
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