You have 12 cards numbered as follows: 2,5,8,10,12,15,18,20,10,7,9,11. What is the probability of choosing an even number, given that it is a multiple of 5? a. 5/12
b. 7/12
c. 1/2
d. 3/5

7/12

Step-by-step explanation:

Simple:

There are 12 numbers in all and only 7 even numbers

Since there are 7 even numbers the probability of rolling an even number is 7/12.

This means that there are 7 outcomes of an even number

Therefore the probability of choosing an even number

=7/12

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°

im pretty sure it would be 5 am, hope that , and give brainliest and guys if this is right then press the button and give 5 stars