Prove: The square of a number that is two more than a multiple of 3 is one more
than a multiple of 3.
=
(3n + 2)2 = [ ? ]n2 + [ ]n +
= [ ]n2 + [ ]n +
In + [ ] +1
= [][]n2 + []n + [])+1
= 1 more than a multiple of 3

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