Sally has 2 pets in her house. The weight of her dog is 50 pounds and the weight of her cat is 12 pounds. By how much is the weight of the dog more than the weight of the cat? A. 38 lb.
B. 30 lb.
C. 28 lb.
D. 20 lb.

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18

m∠5 + m∠3 = m∠1   is true.

m∠5 + m∠6 = 180 is true

m∠2 +m∠3 = m∠6   is true

m∠2 +m∠3 +m∠5 = 180   is true

8 < i think

hope this !

f(y)= y^2-10y+25

step-by-step explanation: