The polynomial f(x) is written in factored form: f(x) = (X-6)(x + 5)(X - 9)
What are the zeros of the polynomial function?
O x= 6, X = -5, X = 9
Ox= 6, X = 5, X = 9
Ox= -6. X = 5. X = -9
O x = -6, X = 6, X = -5, x= 5, X = -9. X = 9

i dont know

step-by-step explanation:

it’s the first one your welcome

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.