One equation in a system of equations is y = 3x + 1. Which of the following would be the second equation so that the system has (0, 5) as its only solution? y = x + 7

y = 3x + 6

y = -x + 5

y = -3x + 1

So the first thing we do is to multiply the top equation by 3. the reason i want to do this is i notice there will be a 6y on both equations and can possibly add/subtract them. so we get 6y = -3x + 27. adding that and the second equation we get 6x = 27-15 which is 12. divide by 6 and we get 2. ∴ x = 2. substituting 2 into the first equation we get 2y = -2 + 9 which is 7. divide by 2 and we get 7/2. ∴ y = 7/2, x = 2.