1. The list below shows the ages of the first 20 customers at a new computer game store, plan to a
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6, 7, 9, 10, 14, 15, 16, 17, 20, 26, 26, 29, 31, 34, 35, 38, 40, 51, 59, 67
a) Decide what class intervals to use, and then create a frequency table for the ages. (4 points: 2
points for intervals, 2 points for frequencies)
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Age
Frequency

-6 is the correct option from the above given options

b

step-by-step explanation:

step-by-step explanation:

part a. the differences are decreasing, so we know the sequence is not arithmetic. the ratios are constant (=3/4), so we know the sequence is geometric.

part b. from part a, we know the common ratio is 3/4, so each term is 3/4 of the one before. the initial term is the number of gallons at h=1.

g[h] = (3/4)·g[h-1]

g[1] = 384 . . . . initial value required for a recursive definition

part c. the general formula for a geometric sequence is

a[n] = a[1]·r^(n-1)

we have a[1] = 384, r = 3/4, and the term number given by h. the formula that follows is

g[h] = 384·(3/4)^(h-1)

part d. filling in the value and doing the arithmetic, we have

g[12] = 384·(3/4)^11 ≈ 384·0.042235136 ≈ 16.2183 . . gallons

part e. each gallon is 4 quarts, so

16.2183 gal × 4 qt/gal = 64.8732 qt