45-45-90 special right triangle
please explain how to solve thank you!

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)

3.07*10^-4

move the decimal 4 places to the left

.000307

b. is the answer xx

answer : the point moved thirteen places to the right

on the number line, a point is moved from -8 to 5

on a number line, negative numbers on the left side of 0   and positive numbers on the right side of 0.

to move from -8 to 5 , we move to the left

start from -8 , move to -7 then -6 then -5 then -4 then -3 then -2 then -1 then 0 then 1 then 2 then 3 then 4 and finally 5

so we moved 13 placed to the right.

the point moved thirteen places to the right