A number of two digits is increased by 54 when the digits are reversed. The ten digits is three times the unit digit. Find the number​

Let n be the unknown number. We can write it as

n = 10a + b

with a and b integers between 1 and 9 (either with positive or negative sign).

Reversing the digits gives another number

m = 10b + a

The first number is increased by 54 when the digits are reversed, which means

m = n + 54   →   10b + a = 10a + b + 54   →   9b - 9a = 54   →   b - a = 6

The digit in the tens place of n is 3 times the digit in the ones place, so

a = 3b

Substitute this into the previous equation and solve for b :

b - a = b - 3b = -2b = 6   →   b = -3

Solve for a :

a = 3b = 3(-3) = -9

Then the original number is n = 10a + b = 10(-9) + (-3) = -93

he used the algebra tiles correctly.

step-by-step explanation:

given : 3x(2x-1)

solution :

since he used algebra tiles .

armando's solution is the same in the solution shown in figure

as he distributed 2x into x and x and wrote them vertically

and also write   -1 vertically

and 3x into x and x and x and wrote it horizontally

performing the multiplication in the algebra tiles we get

and solving the given expression :

3x(2x-1)

since solving the expression using tiles   and solving the expression algebraically we get the same answer

thus   we can choose the first statement as the answer to this problem which is "he used the algebra tiles correctly".

6 cm

step-by-step explanation: