What is the area of a quadrilateral with vertices at (6,1), (12,1), (6,3), and (12,3)? Enter the answer in the box.
units squared

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.

x> 6

step-by-step explanation:

8x+8> 7x+14

8x-7x> 14-8

x> 6

answer: 800

step-by-step explanation:

and?

step-by-step explanation: