Keisha wants to find log537, but her calculator only calculates logs to the base 10. Which formula can she use to find the correct value of log537? alog537=12log1037
blog537=2 log1037
clog537=log1037log105
dlog537=(log105) (log1037)

The 3rd quadrant as 3x+g5ti=56i: 92d-543

Okay so n is going to represent our first number. since the second number of five times greater than n, the second number will be represented as 5n. for us to figure out the two  numbers we need to have  the value of n first. this is going to be done by adding the two numbers together, n and 5n. it can be simplified as 6n, which the problem states is equal to 72. divide 72 by 6n and you can solve for n.  n+5n=726n=72n=(72/6)n=12  now that we know the value of n, we have to multiply 5 times 12 which equals 60. so our two numbers/integers are 12 and 60

Ithink the answer is d