What is the slope line perpendicular to the equation 4x+3y=9

m=3/4

Step-by-step explanation:

first, let's put the line 4x+3y=9 from standard form (ax+by=c) into slope-intercept form (y=mx+b)

we have the equation 4x+3y=9

subtract 4x from both sides

3y=-4x+9

divide by 3

y=-4/3x+3

perpendicular lines have slopes that are negative and reciprocal. If the slopes are multiplied together, the result is -1

so to find the slope of the line perpendicular to the line y=-4/3x+3, we can take the slope of y=-4/3x+3 (-4/3) multiply it by a variable (this is our unknown value), and have that set to -1

(m is the slope value)

-4/3m=-1

multiply by -3/4

m=3/4

therefore the slope of the perpendicular line is 3/4

hope this helps!! :)

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step-by-step explanation:

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v