(x+2)·2x + (x-1)^2= 2 ?

x = 1/3, x = -1.

Step-by-step explanation:

2x(x + 2) + (x - 1)² = 2

Distribute the 2x into x + 2.

2x² + 4x + (x - 1)² = 2

Square (x - 1).

2x² + 4x + x² - x - x + 1 = 2

Combine terms.

2x² + x² + 4x - 2x + 1 = 2

Combine terms again.

3x² + 2x + 1 = 2

Subtract 2 from both sides.

3x² + 2x - 1 = 0

Factor.

(3x - 1)(x + 1) = 0.

Finding the x-values here is the same thing as finding the 0s, so set both of the expressions to 0.

3x - 1 = 0

Add 1 to both sides.

3x = 1

Divide by 3.

x = 1/3.

x + 1 = 0

Subtract 1 from both sides.

x = -1.

3x^2+2x+1 primero lo multiplicas y lo que te de lo sumas y asi sacas 3x^2+2x+1

5/6

step-by-step explanation:

if i remember correctly with perpendicular stuff you just take away the negative