This NASA tracking antenna is a parabolic dish. Its receiver is placed at its focus 27 meters from the center of the dish (its vertex). For this
problem, assume the dish is pointing upward and represent the
vertex as (0,0). Write a parabolic equation that models the cross
section of the antenna dish.

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204

22

step-by-step explanation:

22

56 44 2 4

step-by-step explanation: