Ne positive integer is 4 less than twice another. The sum of their squares is 356. Find the integers

9514 1404 393

  16 and 10

Step-by-step explanation:

Let x and y represent the two integers.

  x = 2y -4 . . . . . one is 4 less than twice another

  x^2 +y^2 = 356 . . . . the sum of their squares is 356

We can solve these using substitution.

  (2y -4)^2 +y^2 = 356 . . . . substitute for x

  5y^2 -16y +16 = 356 . . . .  simpify

  5y^2 -16y -340 = 0 . . . . . put in standard form

  (5y +34)(y -10) = 0 . . . . . . factor*

  y = 10 . . . . . the only positive solution

  x = 2(10) -4 = 16

The integers are 16 and 10.

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* A graphing calculator can provide useful insight as to the factors.

the reason why your question keeps getting deleted because this is not a school related question : )

i will answer your question though.

i never tried church's

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.