A 10-foot ladder leans against a wall so that it is 6 feet high at the top. The ladder is moved so that the base of the ladder travels toward the wall twice the distance that the top of the ladder moves up. How much higher is the top of the ladder now? (Hint: Let 8−2x be the distance from the base of the ladder to the wall.)

Step-by-step explanation:

The Pythagorean Theorem holds for both positions.

The first configuration is an 6-8-10 right triangle.

The second configuration using the Pythagorean Theorem:

10^2 = (8-2x)^2 + (6 + x)^2

100 = 64 - 32x + 4x^2 + 36 + 12x + x^2

100 = 100 - 20x + 5x^2

5x^2 - 20x = 0  

5x(x - 4) = 0

x = 4 feet (we throw out the x = 0 solution as extraneous)

easy math just plug in a and b

step-by-step explanation:

13

step-by-step explanation:

169-1=168

168-3=165

165-5=160

160-7=153

153-9=144

144-11=133

133-13=120

120-15=105

105-17=88

88-19=69

69-21=48

48-23=25

25-25=0

since it took 13times to completely subtract it hence its square root is 13