There are 4 questions easy 1.The triangle ABC has the vertices A(-9, -3) B(1. -3), C(-9, 6)
What is the length of the side between points A and C?
A.9 B.3 C.0 D.6
2. The quadrilateral ABCD has the vertices A(-4, -8), B(6. -8), C(6, 7) D(-4, 7)
what is the length of the side between points A and D
A.16 B.1 C.8 D.15
3. The triangle ABC has the vertices A(-4, -7), B(4,-7) , C(0, 0)
What is the length of the side between points A and B
A.11 B.3 C.14 D.8
4.The quadrilateral ABCD has the vertices
A(-9, -3 ), B(2, -3), C(2, 4) D(-9, 4)

step-by-step explanation:

answer: integers are just whole numbers: positive, negative, and zero.

i = {-∞, -2, -1, 0, 1, 2, 3, ∞}

let x = 1st integer

let y = 2nd integer

x = 3y + 17   {equation 1}

xy = -24         {equation 2}

substitute 3y+17 in place of x n equation 2

and solve for y.

(3y+17)y = -24

3y2 + 17y = -24

3y2 + 17y + 24 = 0

from quadratic equation:

y = [-17±√(172-4(3)(24))]/(2(3))

y = (-17 ±√1)/6

y = (-17+1)/6   or     y = (-17-1)/6

y = -16/6           or     y = -18/6

y = -2 2/3         or   y = -3

since we are dealing with

y = -3

x = 3y+17 = -9+17 = 8

the integers are -3, 8

step-by-step explanation:

slope intercept form is y = mx + b