A basket of snacks contains 8 packs of oreos, 2 bags of chips, 6 packs of gummies, and 4 granola bars. Bill randomly choses 2 snacks. What is the probability a granola bar is chosen one choice after the other without replacing the first bar? {PL HELP}

There is a 3/95 probability that a granola bar is chosen one choice after the other without replacement.

Step-by-step explanation:

The probability of choosing a granola bar without replacing the first bar is 4/20, or 1/5. 4 represents the number of granola bars, and 20 represents the total snacks. Then there are 19 snacks and 3 granola bars which represents the 3/19 chance of getting a granola bar the second time without replacing it.

To find the probability of both of those events happening, multiply them.

(1/5) * (3/19) = 3/95.

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option